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Feb 21, 2013 · 1) Define variables. I assume x refers to frequency, but I'm not sure whether y should refer to V0 or to Gain. 2) What kind of technique do you want to use -- a curve fitting technique (fit y as a function of x or x as a function of y) or a linear interpolation technique. For something like this, linear interpolation is probably easiest.

The slope is found by dividing the change in y-value by the change in x-value, b = the y-intercept, x = the x-value. You will often need to find the value of the x, given values for m and b. For that, you’ll need to use a little algebra. Example: Finding the X-Intercept. Example question: What is the x-intercept of the equation y = 3x – 1?

√y=11-x the square root of a number is always the positive square root therefore y can't be greater than 7 and x can't be greater than 11 look at the perfect squares 1, 4, 9, 16

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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history ...

Select a few x x values, and plug them into the equation to find the corresponding y y values. The x x values should be selected around the vertex. Tap for more steps... Replace the variable x x with 2 2 in the expression. f ( 2) = ( 2) 2 − 6 ⋅ 2 + 11 f ( 2) = ( 2) 2 - 6 ⋅ 2 + 11. Simplify the result.

The syntax for the FIND function in Microsoft Excel is: FIND( substring, string, [start_position] ) Parameters or Arguments substring The substring that you want to find. string The string to search within. start_position Optional. It is the position in string where the search will start. The first position is 1.

The minimum value of C is 0. It occurs when x = 0 and y = 0. The maximum value of C is 32. It occurs when x = 0 and y = 8. A Region that is Unbounded Find the minimum value and the maximum value of C =5x +6y Objective function subject to the following constraints. x ≥0 y ≥0 Constraints x + y ≥5 3x +4y ≥18 SOLUTION The feasible region ...

complete the square to find the equation of the parabola in the problem y = x² + 6x + 11 x^2 + 6x + __ = -11 to complete the square, half the coefficient of x and square it > 3^2 add 9 to both sides x^2 + 6x + 9 = -11 + 9 Factor (x+3)^2 = -2 The square root of both sides x + 3 = +/-extract the square root of -1 which is i x + 3 = +/-two ...

Feb 13, 2020 · Transcript. Ex 2.1, 11 Find the value of tan−1 (1) + cos−1 (−1/2) + sin-1 (−1/2) Solving tan−1 (1) Let y = tan−1 (1) tan y = 1 tan y = tan (π/4) Range of principal value of tan−1 is (−π/2,π/2) Hence, the principal value of tan-1 (1) is π/4 Rough We know that tan 45° = 1 θ = 45° = 45 × 𝜋/180 = 𝜋/4 Since 1 is positive Principal value is θ i.e. 𝜋/4 Solving cos ...

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$$ = \int_0^\infty x f_X(x) \,\mathrm{d}x = \mathrm{E}(X) $$ Attribution I used the Formulas for special cases section of the Expected value article on Wikipedia to refresh my memory on the proof.

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To find the inverse function of f(x), you solve for x and then you replace x with f(x) and you replace f(x) with x. Your equation is: f(x) = 7x - 2 Solve for x. Add 2 to both sides of this equation to get: f(x) + 2 = 7x Divide both sides of this equation by 7 to get: (f(x) + 2)/7 = x

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Chapter 5: Functions. Learners must be able to determine the equation of a function from a given graph. Discuss and explain the characteristics of functions: domain, range, intercepts with the axes, maximum and minimum values, symmetry, etc.

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The following sample observations were randomly selected. X: 5 3 6 3 4 4 6 8 Y: 13 15 7 12 13 11 9 5 Determine the coefficient of correlation and the coefficient of determination. Interpret the association between X and Y.

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8. Find the solution to the initial value problem y′ −y= 2te2t, y(0) = 1 Solution. Using integral factor method by multiplying the ODE by e−t and use initial condition y(0) = 1 to determine the arbitrary constant in your solution curves. 9. Find the solution of the initial value problem 3

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Chapter 5: Functions. Learners must be able to determine the equation of a function from a given graph. Discuss and explain the characteristics of functions: domain, range, intercepts with the axes, maximum and minimum values, symmetry, etc.

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For each value, there is one value. Select few values from the domain.It would be more useful to select the values so that they are around the value of the absolute value vertex.

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